7x^2+5x-38=0

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Solution for 7x^2+5x-38=0 equation:


Simplifying
7x2 + 5x + -38 = 0

Reorder the terms:
-38 + 5x + 7x2 = 0

Solving
-38 + 5x + 7x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-19 + -7x)(2 + -1x) = 0

Subproblem 1

Set the factor '(-19 + -7x)' equal to zero and attempt to solve: Simplifying -19 + -7x = 0 Solving -19 + -7x = 0 Move all terms containing x to the left, all other terms to the right. Add '19' to each side of the equation. -19 + 19 + -7x = 0 + 19 Combine like terms: -19 + 19 = 0 0 + -7x = 0 + 19 -7x = 0 + 19 Combine like terms: 0 + 19 = 19 -7x = 19 Divide each side by '-7'. x = -2.714285714 Simplifying x = -2.714285714

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-2.714285714, 2}

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